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Thanks Britton, this is exactly what I needed.<br>
Cheers,<br>
<br>
JC<br>
<br>
On 08/03/12 12:36, Britton Smith wrote:
<blockquote
cite="mid:CABfs61mkvUcQcjDbySDC=rp61AtGg2sN2hLv56f7TavjscTMaQ@mail.gmail.com"
type="cite">Hi JC,
<div><br>
</div>
<div>You can always reshape the 3D data array to a 1D array. You
can try something like numpy.reshape. Also, you should be able
to just do grid['Density'] without doing get_data.</div>
<div><br>
</div>
<div>Britton<br>
<br>
<div class="gmail_quote">On Thu, Mar 8, 2012 at 10:25 AM,
Jean-Claude Passy <span dir="ltr"><<a
moz-do-not-send="true" href="mailto:jcpassy@gmail.com">jcpassy@gmail.com</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">
<div bgcolor="#FFFFFF" text="#000000"> Hi all,<br>
<br>
As far as I understand, a:<br>
<br>
<address>------------------------------------</address>
<address>region = pf.h.region(...)</address>
<address>density = region["Density"]</address>
<address> ------------------------------------</address>
<br>
will return the density field without considering cells
that have subcells. How can I access ALL the data stored
in the hdf5 file? I have tried to use <br>
<br>
<address> ------------------------------------</address>
<address>grid = pf.h.grids[i]</address>
<address>rhogrid = grid.get_data("Density")</address>
<address> ------------------------------------</address>
<br>
but I would like to get a 1D array.<br>
Thanks for you help,<br>
<br>
JC<br>
</div>
<br>
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