[yt-users] EnzoDatasetInMemory not working in parallel

[Britton Smith]

Hi again,

Maybe this is a clue.  In _generate_random_grids, self.comm.rank is 0 for
all processors, which would explain why N-1 cores are trying to get grids
that don't belong to them.  Interestingly, mylog.info prints out the
correct rank for each of them.

Britton

On Mon, Jul 13, 2015 at 2:21 PM, Britton Smith <brittonsmith at gmail.com>
wrote:

> Hi Matt,
>
> Thanks for your help.  Adjust by grid._id_offset did not work, but I can
> that what is happening is that all processors are trying to call
> _read_field_names using grid 1, when only processor 0 owns that grid.  I
> will look into why now, but if you have any intuition where to check next,
> that would be awesome.
>
> Thanks,
> Britton
>
> On Mon, Jul 13, 2015 at 1:51 PM, Matthew Turk <matthewturk at gmail.com>
> wrote:
>
>> Hi Britton,
>>
>> What looks suspicious to me is the way it's using grid.id.  This might
>> lead to an off-by-one error.  Can you try it with
>> grid.id-grid._id_offset and see if that clears it up?
>>
>> On Mon, Jul 13, 2015 at 7:42 AM, Britton Smith <brittonsmith at gmail.com>
>> wrote:
>> > Hi all,
>> >
>> > I've recently been trying to use yt's inline analysis functionality with
>> > Enzo and am having some difficultly getting it to work in parallel.  I
>> am
>> > using the development tip of yt.  In serial, everything works fine, but
>> in
>> > parallel, I get the following error:
>> > http://paste.yt-project.org/show/5694/
>> >
>> > It seems that the issue is that yt is not correctly identifying which
>> grids
>> > are available on a given processory for the EnzoDatasetInMemory object.
>> > Does anyone have an idea of how to fix this?  Has anyone else seen this?
>> >
>> > For reference, my user_script is just this:
>> >
>> > import yt
>> > from yt.frontends.enzo.api import EnzoDatasetInMemory
>> >
>> > def main():
>> >     ds = EnzoDatasetInMemory()
>> >     ad = ds.all_data()
>> >     print ad.quantities.total_quantity("cell_mass")
>> >
>> > Thanks for any help,
>> >
>> > Britton
>> >
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