[yt-users] quick question

Matthew Turk matthewturk at gmail.com
Fri Sep 26 12:20:16 PDT 2014


On Fri, Sep 26, 2014 at 2:18 PM, John ZuHone <jzuhone at gmail.com> wrote:
> So we're actually *not* getting a 1D dataset then, in the sense that we will
> be duplicating zones.

No, sorry -- specify one cell along the 2nd and 3rd dimensions, but
have them span the full domain.  THis is what we do internally for 1D
and 2D data for cartesian (and in FLASH, for instance, for
non-Cartesian) but here it's being done manually at ingest.

>
> On Sep 26, 2014, at 3:16 PM, Matthew Turk <matthewturk at gmail.com> wrote:
>
> Hi John,
>
> On Fri, Sep 26, 2014 at 2:14 PM, John ZuHone <jzuhone at gmail.com> wrote:
>
> Hi Matt,
>
> I'm coming back to this thread...
>
> From the docstring:
>
>    connectivity : array_like
>        This should be of size (N,8) where N is the number of zones.
>    coordinates : array_like
>        This should be of size (M,3) where M is the number of vertices
>        indicated in the connectivity matrix.
>
> How would this work for 1D data? Or would it?
>
>
> My suggestion would be to fake it by setting the right edges to be 2pi
> and pi, and feeding in a faux-3D dataset.
>
> -Matt
>
>
> Best,
>
> John
>
> On Aug 29, 2014, at 6:40 AM, Matthew Turk <matthewturk at gmail.com> wrote:
>
> Hi Dan,
>
> The load_hexahedral_mesh option will handle arbitrarily spaced
> coordinate systems.  It accepts the cell boundaries and the cell
> values (so there must be N+1 boundaries) and the argument
> geometry='spherical' will then have it interpret them as spherical
> coordinates.  That should work to get log spaced radius zones.
>
> -Matt
>
> On Fri, Aug 29, 2014 at 12:25 AM, Daniel Whalen <dwhalen1999 at gmail.com>
> wrote:
>
>
>
> I am trying to use yt to visualize 3D spherical coordinate data sets created
> with the ZEUS-MP
> code.  I know yt can directly read in such data, but are there any issues
> when the grid is ratioed
> in the radial coordinate (ie, logarithmically spaced zones in radius).
>
>
> Thanks!
>
>
> Dan Whalen
>
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