[yt-users] athena region problem

[Sam Skillman]

I've posted a PR here:
https://bitbucket.org/yt_analysis/yt/pull-request/448/bugfix-for-units-setup-in-athena/diff

When it is accepted it should do the trick.  Thanks for pointing this out!

Cheers,
Sam


On Wed, Feb 27, 2013 at 10:21 AM, Sam Skillman <samskillman at gmail.com>wrote:

> Darn :).  I see what is wrong.  It doesn't seem that the 'unitary' unit is
> being set up correctly for Athena (it currently ends up being -infinity!).
>  I'll push a fix in a few minutes.
>
> Sam
>
>
> On Wed, Feb 27, 2013 at 10:11 AM, nick moeckel <nickolas1 at gmail.com>wrote:
>
>> in my haste to get an example my zeroes didn't have decimals there (shame
>> on me), but that doesn't fix it.
>>
>> In [37]: lc = [0.0, 0.0, 0.4]
>> In [38]: rc = [1.0, 1.0, 0.6]
>> In [39]: region = pf.h.region(center, lc, rc)
>> In [40]: region.volume()
>> Out[40]: -inf
>>
>>
>> On Wed, Feb 27, 2013 at 6:06 PM, Sam Skillman <samskillman at gmail.com>wrote:
>>
>>> Hi Nick,
>>>
>>> It looks like lc only has 2 values in it.  If fixing that to lc = [0.0,
>>> 0.0, 0.4] works (or still breaks), let us know.
>>>
>>> Cheers,
>>> Sam
>>>
>>>
>>> On Wed, Feb 27, 2013 at 10:02 AM, nick moeckel <nickolas1 at gmail.com>wrote:
>>>
>>>> Hi there,
>>>>
>>>> I'm dealing with some athena data right now, and running into some
>>>> issues with defining regions.
>>>>
>>>> an example, with domain_left_edge = [0, 0, 0], and right_edge = [1, 1,
>>>> 1]
>>>>
>>>> In [18]: center=[0.5,0.5,0.5]
>>>> In [19]: lc = [0,0,0.4]
>>>> In [20]: rc=[1.0,1.0,0.6]
>>>> In [21]: region = pf.h.region(center, lc, rc)
>>>> In [22]: region.volume()
>>>> Out[22]: -inf
>>>>
>>>> I'm able to get at region.quantities, but trying to make a projection
>>>> plot fails.
>>>>
>>>> Interestingly, or maybe not, if I try to do something similar with data
>>>> that has its domain centered on the origin, the volume is finite and
>>>> everything I've tried with plotting works fine. I guess athena support is
>>>> still a bit preliminary, but I thought I'd throw this out there.
>>>>
>>>> best,
>>>> Nick
>>>>
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>>>>
>>>>
>>>
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