[yt-dev] off axis projection in yt-3.0

[Matthew Turk]

Okay, so my guess - although I am away from my laptop/wifi at the moment -
is that somehow the origin is being set to the wrong location.  I can think
of a few possibilities, like the width being twice what it should be or the
default being wrong. Can you try manually specifying the center a priori?
One thing that may be getting confused is the origin coordinates. For off
axis slices, the center always gets mapped to 0,0. I don't think it works
like that for off axis projections, though, where it uses a different
method of setting the center that is with respect to the full domain.
On Nov 14, 2013 4:34 PM, "nick moeckel" <nickolas1 at gmail.com> wrote:

> I loaded it like so:
>
> ds =
> load('output_00010/info_00010.txt',fields=['Density','x-velocity','y-velocity','z-velocity','Pressure'])
>
>
> On Thu, Nov 14, 2013 at 10:31 PM, Nathan Goldbaum <nathan12343 at gmail.com>wrote:
>
>> How did you load the data into yt?  In particular, did you use a units
>> dictionary?
>>
>> On November 14, 2013 at 1:30:46 PM, nick moeckel (nickolas1 at gmail.com<//nickolas1 at gmail.com>)
>> wrote:
>>
>>  The 100 pc box is correct, and the surface density looks fine; the
>> domain is 0 to 1 in all three dimensions.
>>
>>
>> On Thu, Nov 14, 2013 at 10:24 PM, Matthew Turk <matthewturk at gmail.com>wrote:
>>
>>> Hi Nick,
>>>
>>> How do the units compare to what's in your sim? Also, what is your
>>> domain extent? My guess is there is an assumption in the octree floating
>>> point coordinate generation that is missing a domain_left_edge offset.
>>>
>>> Matt
>>>  On Nov 14, 2013 4:21 PM, "nick moeckel" <nickolas1 at gmail.com> wrote:
>>>
>>>>  Hi there,
>>>>
>>>> are off axis projections expected to work for all frontends in 3.0?
>>>> Using Ramses I'm getting some curious results. e.g.
>>>>
>>>> p = OffAxisProjectionPlot(ds, [.1, .1, 1], 'Density',
>>>> north_vector=[0,1,0])
>>>>
>>>> results in
>>>>
>>>> http://i.imgur.com/TzTbh7u.png
>>>>
>>>> where the whole simulation seemt to be squished into one quadrant.
>>>>
>>>> best,
>>>>
>>>> Nick
>>>>
>>>>
>>>>
>>>>
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